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sebanyak 100ml larutan nh3 0,4m kb= 2x10^-5 direaksikan dengan 100ml larutan hcl 0,4m hitung ph larutan garam tersebut

1 Jawaban

  • NH3 + HCl --> NH4Cl
    40. 40. --
    40. 40. 40
    -- -- 40

    [H+] = akar(Kw/Kb × Mgaram × valensi)
    [H+] = akar(10^-14/2x10^-5 × 40/200 × 1)
    [H+] = akar(10^-10)
    [H+] = 10^-5
    pH = 5.
    semoga membantu

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