Dik : 2Log3 = a Dit : a). 2Log27 b). 8Log9 c). 3Log16

a) ²log27 = ²log 3.3.3 = ²log3 + ²log3 + ²log3 = a + a + a = 3a
b) [tex] ^{8} log9 = \frac{log9}{log8} = \frac{log3.3}{log.2.2.2} = \frac{ ^{2} log3.3}{^{2} log.2.2.2} = \frac{^{2} log3 + ^{2} log3}{^{2} log2 + ^{2} log2 + ^{2} log2} = \frac{a+a}{1+1+1}= \frac{2a}{3} [/tex]
c) [tex] ^{3}log16 = \frac{log16}{log3}= \frac{ ^{2} log2.2.2.2}{ ^{2} log3}= \frac{^{2} log2+^{2} log2+^{2} log2+^{2} log2}{^{2} log3} = \frac{1+1+1+1}{a}= \frac{4}{a} [/tex]