Matematika

Pertanyaan

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1 Jawaban

  • No. 3
    keliling lingkaran = phi x d
    22/7 × 28 × 3/4 = 66
    66 + 14 + 14 = 94 cm
    Luas lingkaran = phi x r kuadrat
    22/7 × 14 × 14 × 3/4
    462 cm

    No. 4
    Luas lingkaran = phi x r kuadrat
    1256 = 3,14 × r kuadrat
    r kuadrat = 1256 : 3,14
    r kuadrat = 400
    r = 20 cm

    keliling lingkaran = phi x d
    3,14 x 40
    125,6 cm

    No. 5
    Juring
    135
    ----- × 3,14 × 10 × 10 = 117,5 cm
    360

    No. 6
    lintasan = keliling x putaran
    lintasan = (22/7 × 42) × 500
    lintasan = 66.000 cm = 66 km

    No.7
    ADB = 50°
    AOB = 2× 50°
    100°
    Maka BOC = 80°