Paku setinggi 3 cm berada 15 cm di depan lensa cembung dgn f = 10. jarak bayangan? Tinggi? Perbesaran?

Dik: h = 3 cm, s = 15 cm, f = 10 cm

Jb.
1/s' = 1/f - 1/s
1/s' = 1/10 - 1/15
1/s' = (3 - 2)/30
1/s' = 1/30
s' = 30 cm ✔ (jarak bayangan)

h' = (s'/s) × h
h' = (30/15) × 3
h' = 2 × 3
h' = 6 cm ✔ (tinggi bayangan)

M = s'/s = 30/15
M = 2 kali ✔ (perbesaran bayangan)


Semoga membantu :)