1 keliling segitiga ABCD 50cm, AB=2x cm BC=(x+3)cm dan AC=(3x-1)cm. hitunglah panjang masing masing sisinya! 2 luas suatu segjtiga 36cm jika panjang alasnya 9cm

1.)
K = 2x + (x + 3) + (3x - 1)
50 = 6x + 2
48 = 6x
8 = x

AB = 2x = 2.8 = 16 cm
BC = x + 3 = 8 + 3 = 11 cm
AC = 3x - 1 = 3.8 - 1 = 23 cm

2.)
L = a.t / 2
36 cm" = 9.t / 2
72 cm" = 9 cm . t
72 / 9 = t
8 cm = t

Semoga membantu dan semoga bermanfaat...

1. Keliling ∆ = AB + BC + AC
50 = (2x) + (x + 3) + (3x - 1)
50 = 6x + 2
6x = 48
x = 8 cm

AB = 2x = 2.8 = 16 cm
BC = x + 3 = 8 + 3 = 11 cm
AC = 3x - 1 = 3(8) - 1 = 24 - 1 = 23 cm

2. Luas ∆ = a x t / w
36 = 9 x t / 2
9t = 72
t = 8 cm