Matematika

Pertanyaan

1per 16+1per 8+1 per 4 +...+16
1per 16+1per 8+1 per 4 +...+16

2 Jawaban

  • 1per 16+1per 8+1 per 4 +...+16
    = 15/16 + 15 + 16 
  • Un = ar^n-1
    16 = 1/16 × 2^n-1
    256 (16^2) = 2^n-1
    2^8 = 2^n-1
    8 = n-1
    n = 8 + 1
    n = 9
    Maka jumlah 9 sukunya
    S9 = a (r^n - 1)/ r-1
    S9 = 1/16 (2^9 - 1)/ 2-1
    S9 = 1/16 (512-1)
    S9 = 1/16 (511)
    S9 = 511/16

    Jawabannya A.