1per 16+1per 8+1 per 4 +...+16
Matematika
jess38
Pertanyaan
1per 16+1per 8+1 per 4 +...+16
2 Jawaban
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1. Jawaban Noire
1per 16+1per 8+1 per 4 +...+16
= 15/16 + 15 + 16 -
2. Jawaban rayhan3septian
Un = ar^n-1
16 = 1/16 × 2^n-1
256 (16^2) = 2^n-1
2^8 = 2^n-1
8 = n-1
n = 8 + 1
n = 9
Maka jumlah 9 sukunya
S9 = a (r^n - 1)/ r-1
S9 = 1/16 (2^9 - 1)/ 2-1
S9 = 1/16 (512-1)
S9 = 1/16 (511)
S9 = 511/16
Jawabannya A.