Tolong di jawab ya taman² Secepatnya Terimakasih.

Ingat:
kuadran I   : sin α
kuadran II  : sin (180-α) = sin α
kuadran III : sin (180+α) = -sin α
kuadran IV : sin (360-α) = -sin α


x → y = sin x
0 → y = sin(0) = 0
1/6 π → y = sin(1/6. 180) = sin(30) = 1/2
1/3 π → y = sin(1/3. 180) = sin(60) = 1/2 √2
π/2 → y = sin(180/2) = sin(90) = 1
2/3 π → y = sin(2/3. 180) = sin(120) = sin(180-60) = sin(60) = 1/2 √2
5/6 π → y = sin(5/6. 180) = sin(150) = sin(180-30) = sin(30) = 1/2
π → y = sin(180) = sin(180-0) = sin(0) = 0
7/6 π → y = sin(7/6. 180) = sin(210) = sin(180+30) = -sin(30) = -1/2
4/3 π → y = sin(4/3. 180) = sin(240) = sin(180+60) = -sin(60) = -1/2 √2
3/2 π → y = sin(3/2. 180) = sin(270) = sin(180+90) = -sin(90) = -1
5/3 π → y = sin(5/3. 180) = sin(300) = sin(360-60) = -sin(60) = -1/2 √2