Misalkan f(x) = cos (2 sin x . cos x), maka f'(x) =

f(x) = cos (2sinxcosx)
f'(x) = cos (sin2x)
f'(x) = sin (sin2x) . cos2x. 2
f'(x) = 2sin (2sinxcosx) cos2x
f'(x) = 4 sin²x . cosx . cos2x