fungsi kuadrat f(×)=p×2-4×+3 mempunyai nilai minimum 0.nilai p adalah

f(x) minimum jika f'(x) = 0

f'(x) = 0
2px - 4 = 0
2px = 4
x = 4/2p
x = 2/p

f min = 0
f(2/p) = 0
p×(2/p)^2 - 4×(2/p) + 3 = 0
4/p - 8/p + 3 = 0
-4/p = -3
-3p = -4
p = -4/-3
p = 4/3

jd nilai p = 4/3

f(x) = px^2 - 4x + 3 nilai minimumnya = 0
D/(-4a) = 0
D = 0
b^2 - 4ac = 0
(-4)^2 - 4(p)(3) = 0
16 - 12p = 0
-12p = -16
p = 16/12 = 4/3