Matematika

Pertanyaan

Bila 3log 2=1 dam 3log 5=b maka 6 log 30

1 Jawaban

  • 6log30 = 6log2.3.5
    =6log2+6log3+6log5

    # 6log2 = 2log2/2log6 = 1 /2log2.3 = 1 /2log2+2log3 = 1 /1+1 = 1/2

    # 6log3 = 3log3/3log6 = 1 /3log2.3 = 1 /3log2+3log3 = 1 /1+1 = 1/2

    # 6log5 = 3log5/3log6 = 3log5 /3log2.3 = 3log5 /3log2+3log3 = b/ 1+1 = b/2

    Maka >>> 6log2 + 6log3 + 6log5 = 1/2 + 1/2 + b/2 = 2+b /2 atau 1+ b/2.

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