jika 2log 3 =a dan 8log 6 =

2 log 3 = a
6 log 8 = 2 log 8 / 2 log 6
= 2 log 2^3 / 2 log 2.3
= 3 { 2 log 2 } / { 2 log 2 + 2 log 3 }
= 3 / { 1 + a }
maaf jika salah kak ^_^

2log3 = a
8log6 = 2^3log6
= 1/3 (2log6)
= 1/3 (2log3.2)
= 1/3 (2log3 + 2log2)
= 1/3 (a + 1)

= (a + 1)/3