3. Hitunglah keliling dan luas masing masing bangun datar tersebut!

K = 5+5+3+3+8 = 24 cm
L = a x t / 2 + p x l
= 8 x 3(phytagoras) / 2 + 3 x 8
= 12 + 24
= 36 cm^2

Keliling total = 5+5+3+3+8 = 24
Keliling segitiga = 5+5+8 = 18
Keliling prs pjg = 8 +8+3+3 = 22
Tinggi segitiga dgn phytagoras = 3
Luas segitiga = 1/2 ×8×3 =12
Luas prs pjg = 3×8 = 24