(2 log4+ 2 log6)x 24 log32

Bab Logaritma

(2log 4 + 2log 6) × 24 log 32
= (2log (4 × 6)) × 1/(32 log 24)
= 2log 24 × 1/(1/5 × 2log 24)
= 2log 24 × 5/(2log 24)
= 5

Bab Logaritma
Matematika SMA Kelas X

(²log 4 + ²log 6) x ^24log 32
= (²log (4 x 6)) x ^24log 32
= ²log 32 x ^24log 24
= ²log (2^5) x 1
= 5