Sin a = 1/2 dan cos a = -1/2 √3 carilah nilai tangen a

sin a = 1/2
a = 30°

cos a = -1/2 akar 3
a = 30°

maka
tan a
= tan 30°
= 1/3 akar 3

tan a
= sin a ÷ cos a
= 1/2 ÷ -1/2 √3
= 1/2 x -2 ÷ √3
= -2 ÷ √3
= (-2 ÷ √3) x (√3 ÷ √3)
= - 2/3 √3