Tlng banntu jwb Misalkan y=(x-3)(x²+7x-1) maka y'=

y=uv -> y'=u'v+uv'
y=(x-3)(x²+7x-1)
y'= (x)(x²+7x-1)+(x-3)(2x+7)
y'=x³+7x²-x+2x²+7x-6x-21
y'=x³+9x²-21

Rumus:
y = u.v
y' = u'.v + u.v'

Penyelesaian: 
y = (x - 3)(x² + 7x - 1) 
y' = 1.(x² + 7x - 1) + (x - 3).(2x + 7)
y' = x² + 7x - 1 + 2x² + x - 21
y' = 3x² + 8x - 22