jika a log b +b log a = 2 maka hubungan antara a dan b adalah a. a2 + b2 = 1 b. 2a- b = 0 c. a-b = a+ b d. 2b = a e. a-b = 0 tolong caranya makasih

log b/log a + log a/log b = 2
(log b*log b) + log a*log a)/loga*logb = 2

anggap log a = x
angga log b = y

(x^2 + y^2 )/xy = 2
x^2 + y^2 = 2xy
x^2 -2xy + y^2 = 0
(x-y)^2 = 0
x - y = 0
x = y

log a = log b
log a - log b = 0
log (a/b) = 0
log (a/b) = log 1

a/b = 1
a = b
a - b = 0