Jika a dan b adalah akar akar persamaan kuadrat x^2-3x-1=0 maka a^4+6a^2b^2+b^4=......

x^2 - 3x - 1 = 0
a + b = -(-3)/1 = 3
a.b = -1/1 = -1
a^2 + b^2 = (a + b)^2 - 2ab = (3)^2 - 2(-1) = 9 + 2 = 11

a^4 + 6a^2.b^2 + b^4
= a^4 + 2a^2.b^2 + b^4 + 4a^2.b^2
= (a^2 + b^2)^2 + 4(ab)^2
= (11)^2 + 4(-1)^2
= 121 + 4
= 125