diketahui f(x)=(x^2-5)^2/3+1 maka f^-1 =...

(x²-5)^2/3 + 1 = y
(x² - 5)^2/3 = y - 1
x² - 5 = (y - 1)^3/2
x² = 5 + √(y-1)³
x = √{5 + √(y-1)³}
f-¹(x) = √{5 + √(x-1)³}