a. 120.10^-2 b. 60.10^-2 c. 12.10^-2 d.6.10^-2 e. 1,2.10^-2
Kimia
shiwinta
Pertanyaan
a. 120.10^-2
b. 60.10^-2
c. 12.10^-2
d.6.10^-2
e. 1,2.10^-2
b. 60.10^-2
c. 12.10^-2
d.6.10^-2
e. 1,2.10^-2
1 Jawaban
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1. Jawaban vinantun
(NO)^m __(0,1/0,2)^m 24×10^-2/48×10^-2. (1/2)^m = 1/2. m=1.
(Br2)^n___(0,1/0,2)^n=6×10^-2/24×10^-2.maka (1/2)^n= (1/2)^2. n = 2. maka: v= k (NO)(Br2)^2.masuk pers 1:
6×10^-2= k(0,1 )(0,1)^2
k=6×10^1. k= 60.
maduk data luar tabel:
v= 60(0,2)(0,1)^2
=120×10^-2.jadi laju reaksi bila(NO)=0,2 dan (Br2)= 0,1 adalah : 120×10^-2.