jika Tan a = 5/12 dengan phi

tanx = 5/12
tanx = de/sa

→ depan = 5
→ samping = 12

→ Sisi miring :
= √12² + 5²
= √144 + 25
= √169
= 13

180 < x < 270

- sinx = de/mi = -5/13
- cosx = sa/mi = -12/13
- tanx = de/sa = 5/12

sin2x + 4cosx

= 2sinxcosx + 4cosx

= 2(-5/13)(-12/13) + 4 (-12/13)

= 2 (60/169) - 48/13

= 120/169 - 624/169

= -504/169

=