Tentukan volume 9 gram gas etana,C2H6 (C=12 H=1) jika diukur pada keadaan standar.

Keadaan standar / STP = 22,4
Mr C2H6 = 2*12 + 6*1 = 24 + 6 = 30
G = 9 gram = 9000 mg

Volume = mol * 22,4
Volume = G / Mr * 22,4
Volume = 9000 / 30 * 22,4
Volume = 6720 ml

semoga bermanfaat

Massa = 9 gram
Keadaan STP
Mr C2H6
= 2xAr C + 6xAr H
= 24 + 6
= 30

n C2H6
= massa / Mr
= 9 / 30
= 0,3 mol

Volume
= n x 22,4
= 0,3 x 22,4
= 6,73 liter