tolong dong nomor 32
Fisika
billy1410
Pertanyaan
tolong dong nomor 32
1 Jawaban
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1. Jawaban cingcang
32][
lensa cembung
f = 20 cm
s = 30 cm ← ruang 2
m = __?
s' = __?
perbesaran
m = f / (s - f)
m = 20 / (30 - 20)
m = 2 kali ← jwb
jarak bayangan
s' = m • s
s' = 2 • (30 cm)
s' = 60 cm ← jwb