tolong jawab nomor 13

(fog)(x)=x²-4x+10, g(x)=x-3
f(g(x))=x²-4x+10
f(x-3)=x²-4x+10
misal : x-3 = p
               x  = p+3 , p diganti x menjadi (x+3)
f(x)=(x+3)²-4(x+3)+10
     =x²+6x+9-4x-12+10
     =x²+2x+7

(f o g)(x) = x^2 - 4x + 10
f(g(x)) = x^2 - 4x + 10
f(x - 3) = x^2 - 4x + 10
Misal (x - 3) = a => x = a + 3
f(a) = (a + 3)^2 - 4(a + 3) + 10
f(a) = a^2 + 6a + 9 - 4a - 12 + 10
f(a) = a^2 + 2a + 7
f(x) = x^2 + 2x + 7

^ = pangkat