Matematika

Pertanyaan

1. lim x-a : sin (x-a)-2x+2a dimana x mendekati a adalah....
2. lim (t^2-5t+6) sin (t-2) : (t^2-t-2)^2 dimana t mendekati 2 adalah...

1 Jawaban

  • 1) Lim (x - a) / [sin (x - a) - 2x + 2a]
    = Lim (x - a) / [sin (x - a) - 2(x - a)] ====>kali [1/(x - a)] / [1/(x - a)]
    = Lim (x - a)/(x - a) / [(sin (x - a))/(x - a) - 2(x - a)/(x - a)]
    = 1 / [1 - 2]
    = 1/(-1)
    = -1

    2) Lim (t^2 - 5t + 6) sin (t - 2) / (t^2 - t - 2)^2
    = Lim (t^2 - 5t + 6) sin (t - 2) / (t^2 - t - 2)(t^2 - t - 2)
    = Lim (t - 2)(t - 3) sin (t - 2) / (t - 2)(t + 1)(t - 2)(t + 1))
    = Lim (t - 3) sin (t - 2) / (t + 1)^2 (t - 2)
    = Lim (t - 3)/(t + 1)^2 . (sin (t - 2))/(t - 2)
    = (2 - 3)/(2 + 1)^2 . 1/1
    = (-1) / 3^2 . 1
    = -1/9

Pertanyaan Lainnya