Matematika

Pertanyaan

tolong bantu perbandingan
tolong bantu perbandingan

1 Jawaban

  • P = 5 × n = 5n

    l = 3 × n = 3n

    T = 2 × n = 2n


    V = P × l × T

    810 = 5n × 3n × 2n

    810 = 30n^3

    n^3 = 810 ÷ 30

    n^3 = 27 (diakarkan pangkat 3)

    n^3 = 3


    jdi

    P = 5 × n = 5 × 3 = 15 cm

    l = 3 × n = 3 × 3 = 9 cm

    T = 2 × n = 2 × 3 = 6 cm


    jdi


    L = 2 × (p×l + p×t + l×t)

    = 2 × (15×9 + 15×6 + 9×6)

    = 2 × (135 + 90 + 54)

    = 2 × 279

    = 558 cm^2 (C)