Tolong kak beserta caranya ya:) dibantu

1. m(gr)=n×mr(Fe2 (SO4))
             = 2×(400)=800 gr
2. n= m(gr)/mr(Al2(SO4)
      = 3,42/342 = 0,01
3. n= 1,806* 10^{24} /6.02*10²³ = 3
     V stp = 3*22,4 =67,2ml
4. n= 4,48/22,4 =0,2 mol
    0,2×6,02*10²³=1,204 ×10²³ molekul
5. n=6,72/22,4=0,3 mol
    m(gr)= 0,3×28= 8,4 gr
6. n=1,204*10^{24}/6,02*10²³=2 mol
    m(gr)= 2*56=112 gr