limit x->3 √2x+3 - √4x-3 / 3-x

ini jawabannya, semoga membantu yaa :)

cara lain
dgn Lhospital

lim(x->3) √(2x+3) - √(4x-3) /(3-x)
lim(x->3) [(2x+3)¹/² - (4x-3)¹/²] / (3 - x)

= 1/2 (2) (2x+3)⁻¹/²  -(1/2 (4)(4x-3)⁻¹/2 )  /(-1)
= - [(2x +3)⁻¹/² - 2(4x-3)⁻¹/²]
x= 3
= -[(9)⁻¹/²  - 2(9)⁻¹/²]
= - [ 1/3 - 2/3]
= 1/3